hoe de leeftijd te berekenen op basis van de geboortedatum in dit formaat 24-6-1976 ma/datum/jaar…
Antwoord 1, autoriteit 100%
Veel van deze antwoorden houden geen rekening met schrikkeljaren en daarom kun je het beste de methoden van Apple gebruiken in plaats van te delen door constanten.
Snel
let birthday: NSDate = ...
let now = Date()
let ageComponents = calendar.dateComponents([.year], from: birthday, to: now)
let age = ageComponents.year
Doelstelling-C
NSDate* birthday = ...;
NSDate* now = [NSDate date];
NSDateComponents* ageComponents = [[NSCalendar currentCalendar]
components:NSCalendarUnitYear
fromDate:birthday
toDate:now
options:0];
NSInteger age = [ageComponents year];
Ik denk dat dit schoner en nauwkeuriger is dan alle andere antwoorden hier.
Bewerken
Verhoog de nauwkeurigheid door zowel birthdayals nowin te stellen op 12.00 uur. Hier is een manier om dat te doen met een Dateextensie (in Swift)…
/// Returns a new date identical to the receiver except set to precisely noon.
/// Example: let now = Date().atNoon()
func atNoon() -> Date {
var components = (Calendar.current as NSCalendar).components([.day, .month, .year, .era, .calendar, .timeZone], from: self)
components.hour = 12
components.minute = 0
components.second = 0
components.nanosecond = 0
return Calendar.current.date(from: components)!
}
Antwoord 2, autoriteit 3%
Zo kunt u uw werkelijke leeftijd berekenen op basis van uw geboortedatum in jaren en dagen:
NSString *birthDate = @"03/31/1990";
NSDate *todayDate = [NSDate date];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"MM/dd/yyyy"];
int time = [todayDate timeIntervalSinceDate:[dateFormatter dateFromString:birthDate]];
int allDays = (((time/60)/60)/24);
int days = allDays%365;
int years = (allDays-days)/365;
NSLog(@"You live since %i years and %i days",years,days);
Het geeft de jaren en de exacte dagen terug. En als je het nodig hebt, kun je de NSDateFormatter en nog veel meer wijzigen.
Antwoord 3, autoriteit 2%
Dit is de code die ik heb gekregen van deze link.. het werkt geweldig.. De output zal ongeveer “5 jaar 6 maanden” zijn en alle usecases worden erin behandeld.
- (NSString *)age:(NSDate *)dateOfBirth {
NSInteger years;
NSInteger months;
NSInteger days;
NSCalendar *calendar = [NSCalendar currentCalendar];
unsigned unitFlags = NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay;
NSDateComponents *dateComponentsNow = [calendar components:unitFlags fromDate:[NSDate date]];
NSDateComponents *dateComponentsBirth = [calendar components:unitFlags fromDate:dateOfBirth];
if (([dateComponentsNow month] < [dateComponentsBirth month]) ||
(([dateComponentsNow month] == [dateComponentsBirth month]) && ([dateComponentsNow day] < [dateComponentsBirth day]))) {
years = [dateComponentsNow year] - [dateComponentsBirth year] - 1;
} else {
years = [dateComponentsNow year] - [dateComponentsBirth year];
}
if ([dateComponentsNow year] == [dateComponentsBirth year]) {
months = [dateComponentsNow month] - [dateComponentsBirth month];
} else if ([dateComponentsNow year] > [dateComponentsBirth year] && [dateComponentsNow month] > [dateComponentsBirth month]) {
months = [dateComponentsNow month] - [dateComponentsBirth month];
} else if ([dateComponentsNow year] > [dateComponentsBirth year] && [dateComponentsNow month] < [dateComponentsBirth month]) {
months = [dateComponentsNow month] - [dateComponentsBirth month] + 12;
} else {
months = [dateComponentsNow month] - [dateComponentsBirth month];
}
if ([dateComponentsNow year] == [dateComponentsBirth year] && [dateComponentsNow month] == [dateComponentsBirth month]) {
days = [dateComponentsNow day] - [dateComponentsBirth day];
}
if (years == 0 && months == 0) {
if (days == 1) {
return [NSString stringWithFormat:@"%d day", days];
} else {
return [NSString stringWithFormat:@"%d days", days];
}
} else if (years == 0) {
if (months == 1) {
return [NSString stringWithFormat:@"%d month", months];
} else {
return [NSString stringWithFormat:@"%d months", months];
}
} else if ((years != 0) && (months == 0)) {
if (years == 1) {
return [NSString stringWithFormat:@"%d year", years];
} else {
return [NSString stringWithFormat:@"%d years", years];
}
} else {
if ((years == 1) && (months == 1)) {
return [NSString stringWithFormat:@"%d year and %d month", years, months];
} else if (years == 1) {
return [NSString stringWithFormat:@"%d year and %d months", years, months];
} else if (months == 1) {
return [NSString stringWithFormat:@"%d years and %d month", years, months];
} else {
return [NSString stringWithFormat:@"%d years and %d months", years, months];
}
}
}
Als je leeftijd als int wilt, probeer dan het volgende antwoord.. die ik kreeg door link
- (NSInteger)age:(NSDate *)dateOfBirth {
NSCalendar *calendar = [NSCalendar currentCalendar];
unsigned unitFlags = NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay;
NSDateComponents *dateComponentsNow = [calendar components:unitFlags fromDate:[NSDate date]];
NSDateComponents *dateComponentsBirth = [calendar components:unitFlags fromDate:dateOfBirth];
if (([dateComponentsNow month] < [dateComponentsBirth month]) ||
(([dateComponentsNow month] == [dateComponentsBirth month]) && ([dateComponentsNow day] < [dateComponentsBirth day]))) {
return [dateComponentsNow year] - [dateComponentsBirth year] - 1;
} else {
return [dateComponentsNow year] - [dateComponentsBirth year];
}
}
Ik hoop dat dit iemand helpt..
Antwoord 4
Als u alleen de leeftijd wilt vinden, gebruik dan hieronder een die ook een schrikkeljaarberekening bevat
- (NSInteger)age:(NSDate *)dateOfBirth {
NSCalendar *calendar = [NSCalendar currentCalendar];
unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
NSDateComponents *dateComponentsNow = [calendar components:unitFlags fromDate:[NSDate date]];
NSDateComponents *dateComponentsBirth = [calendar components:unitFlags fromDate:dateOfBirth];
if (([dateComponentsNow month] < [dateComponentsBirth month]) ||
(([dateComponentsNow month] == [dateComponentsBirth month]) && ([dateComponentsNow day] < [dateComponentsBirth day]))) {
return [dateComponentsNow year] - [dateComponentsBirth year] - 1;
} else {
return [dateComponentsNow year] - [dateComponentsBirth year];
}
}
Antwoord 5
Een eenvoudig te gebruiken snelle extensie om de leeftijd/hoe oud is een NSDate
te achterhalen
extension NSDate {
var age: Int {
let calendar: NSCalendar = NSCalendar.currentCalendar()
let now = calendar.startOfDayForDate(NSDate())
let birthdate = calendar.startOfDayForDate(self)
let components = calendar.components(.Year, fromDate: birthdate, toDate: now, options: [])
return components.year
}
}
Voorbeeld:
NSDate(timeIntervalSince1970:0).age // => 45 (as of nov 2015) Epoch happened 45 year ago !
Trouwens, je moet voorzichtig zijn, dit is de westerse opvatting van leeftijd, het tellen is anders in sommige andere landen (Koreabijvoorbeeld).
Antwoord 6
Misschien heb ik het mis, maar dit is eenvoudiger, nietwaar?
NSTimeInterval ageInterval = [birthDate timeIntervalSinceDate:[NSDate date]];
NSInteger age = ABS(ageInterval / (60 * 60 * 24 * 365));
Antwoord 7
Methode in Swift 3+syntaxis gebaseerd op cobbal’s oplossing.
func calculateAgeInYearsFromDateOfBirth (birthday: Date) -> Int {
let now = Date()
let calendar = Calendar.current
let ageComponents = calendar.dateComponents([.year], from: birthday, to: now)
let age = ageComponents.year!
return age
}
Antwoord 8
de gemakkelijkste manier is om de NSCalendar te gebruiken:
NSDate *_dateOfBirth = ...;
NSDateComponent *_diff = [[NSCalendar currentCalendar] components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:_dateOfBirth toDate:[NSDate date] options:0];
NSLog(@"%@", _diff);
Antwoord 9
-(NSInteger) ComputeYearMonth
{
NSDateFormatter *format = [[NSDateFormatter alloc] init];
[format setDateFormat:@"yyyy-MM-dd"];
NSDate *DateOfBirth=[format dateFromString:[NSString stringWithFormat:@"%@-%@-%@",year,month,day]];
NSDate *currentTime = [NSDate date];
NSLog(@"DateOfBirth======%@",DateOfBirth);
NSInteger years = [[[NSCalendar currentCalendar] components:NSYearCalendarUnit
fromDate:DateOfBirth
toDate:currentTime options:0]year];
NSInteger months = [[[NSCalendar currentCalendar] components:NSMonthCalendarUnit
fromDate:DateOfBirth
toDate:currentTime options:0]month];
NSLog(@"Number of years: %d",years);
NSLog(@"Number of Months: %d,",months);
return years;
// End of Method
}
Antwoord 10
Hier is een functie om de leeftijd te berekenen (Swift 2.1)
func calculateAge (birthday: NSDate) -> NSInteger {
let calendar : NSCalendar = NSCalendar.currentCalendar()
let unitFlags : NSCalendarUnit = [NSCalendarUnit.Year, NSCalendarUnit.Month, NSCalendarUnit.Day]
let dateComponentNow : NSDateComponents = calendar.components(unitFlags, fromDate: NSDate())
let dateComponentBirth : NSDateComponents = calendar.components(unitFlags, fromDate: birthday)
if ( (dateComponentNow.month < dateComponentBirth.month) ||
((dateComponentNow.month == dateComponentBirth.month) && (dateComponentNow.day < dateComponentBirth.day))
)
{
return dateComponentNow.year - dateComponentBirth.year - 1
}
else {
return dateComponentNow.year - dateComponentBirth.year
}
}
Antwoord 11
let birthday = NSCalendar.currentCalendar().dateWithEra(1, year: 2016, month: 07, day: 25, hour: 8, minute: 53, second: 0, nanosecond: 0)!
func calculateAge(birthday: NSDate) -> String {
func grammaticalString(forUnit unit: String, value: Int) -> String {
if value > 1 {
return "\(value) \(unit)s"
} else {
return "\(value) \(unit)"
}
}
let calendar = NSCalendar.currentCalendar()
let unitFlags: NSCalendarUnit = [NSCalendarUnit.Year, NSCalendarUnit.Month, NSCalendarUnit.Day, NSCalendarUnit.Hour, NSCalendarUnit.Minute]
let ageComponent = calendar.components(unitFlags, fromDate: birthday, toDate: NSDate(), options: [])
let years = ageComponent.year
let months = ageComponent.month
let days = ageComponent.day
let hours = ageComponent.hour
switch (years, months, days, hours) {
case (let y, let m, _, _) where y > 0:
return "\(grammaticalString(forUnit: "Year", value: y)) \(grammaticalString(forUnit: "Month", value: m))"
case (let y, let m, let d, _) where y == 0 && m > 0:
return "\(grammaticalString(forUnit: "Month", value: m)) \(grammaticalString(forUnit: "Day", value: d))"
case (let y, let m, let d, _) where y == 0 && m == 0 && d > 0:
return "\(grammaticalString(forUnit: "Day", value: d))"
case (let y, let m, let d, let h) where y == 0 && m == 0 && d == 0 && h > 0:
return "\(grammaticalString(forUnit: "Hour", value: h))"
case (let y, let m, let d, let h) where y == 0 && m == 0 && d == 0 && h == 0:
if ageComponent.minute > 0 {
return "\(grammaticalString(forUnit: "Minute", value: ageComponent.minute))"
} else {
return "-"
}
default:
return "-"
}
}
// Output will be any of these
// 2 Years 3 Months
// 3 Months 0 Days
// 2 Days
// 3 Hours
// 45 Minutes
// -